Question:medium

The number of odd factors of \(24!\) is

Show Hint

To find the number of odd factors of \(n!\), \[ \boxed{\text{Ignore the exponent of }2} \] and multiply \[ \boxed{(e_1+1)(e_2+1)\cdots} \] using only the exponents of the odd prime factors.
Updated On: Jul 18, 2026
  • \(23450\)
  • \(23\)
  • \(10560\)
  • \(76954\)
Show Solution

The Correct Option is C

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