Question

The number of electrons delivered at the cathode during electrolysis by a current of $1$ ampere in $60$ seconds is (change on electron = $1.60 \times 10^{-19} C)$

• A. $6 \times 10^{23}$
• B. $6 \times 10^{20}$
• C. $3.75 \times 10^{20}$
• D. $7.48 \times 10^{23}$

Answer 1

The Correct Option is C

To find the number of electrons delivered at the cathode during electrolysis, we use the formula:

n = \frac{I \cdot t}{e}

where:

• n is the number of electrons,
• I is the current in amperes,
• t is the time in seconds,
• e is the charge of one electron in coulombs.

Given values:

• I = 1 \, \text{ampere}
• t = 60 \, \text{seconds}
• e = 1.60 \times 10^{-19} \, \text{C}

Substituting the given values into the formula:

n = \frac{1 \times 60}{1.60 \times 10^{-19}}

Calculate the numerator:

n = \frac{60}{1.60 \times 10^{-19}}

Perform the division:

n = 3.75 \times 10^{20}

Thus, the number of electrons delivered at the cathode is 3.75 \times 10^{20}, which matches the correct answer option provided.