Question:medium

The number of corner points of the feasible region determined by constraints \(x \geq 0\), \(y \geq 0\), \(x + y \geq 4\) is:

Show Hint

When determining corner points for feasible regions, find all intersections of the constraint boundaries and check where they satisfy the constraints.
Updated On: Jan 13, 2026
  • \(0\)
  • \(1\)
  • \(2\)
  • \(3\)
Show Solution

The Correct Option is C

Solution and Explanation

To determine the number of corner points for the feasible region, we analyze the given constraints: 1. \(x \geq 0\): This defines the region to the right of and including the \(y\)-axis. 2. \(y \geq 0\): This defines the region above and including the \(x\)-axis. 3. \(x + y \geq 4\): This defines the region above the line \(x + y = 4\). This line can be rewritten as \(y = 4 - x\), intersecting the axes at \(x = 4\) and \(y = 4\). The feasible region is the intersection of these conditions, located in the first quadrant (\(x \geq 0\), \(y \geq 0\)) and above the line \(x + y = 4\). Although this region is unbounded, it possesses two corner points: the intersection of \(x + y = 4\) with \(x = 0\), which is \((0, 4)\), and the intersection of \(x + y = 4\) with \(y = 0\), which is \((4, 0)\). Therefore, there are \(2\) corner points. The correct answer is (C).

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