To determine the number of corner points for the feasible region, we analyze the given constraints: 1. \(x \geq 0\): This defines the region to the right of and including the \(y\)-axis. 2. \(y \geq 0\): This defines the region above and including the \(x\)-axis. 3. \(x + y \geq 4\): This defines the region above the line \(x + y = 4\). This line can be rewritten as \(y = 4 - x\), intersecting the axes at \(x = 4\) and \(y = 4\). The feasible region is the intersection of these conditions, located in the first quadrant (\(x \geq 0\), \(y \geq 0\)) and above the line \(x + y = 4\). Although this region is unbounded, it possesses two corner points: the intersection of \(x + y = 4\) with \(x = 0\), which is \((0, 4)\), and the intersection of \(x + y = 4\) with \(y = 0\), which is \((4, 0)\). Therefore, there are \(2\) corner points. The correct answer is (C).
Consider the line \[ \vec{r} = (\hat{i} - 2\hat{j} + 4\hat{k}) + \lambda(-\hat{i} + 2\hat{j} - 4\hat{k}) \]
Match List-I with List-II:
| List-I | List-II |
|---|---|
| (A) A point on the given line | (I) \(\left(-\tfrac{1}{\sqrt{21}}, \tfrac{2}{\sqrt{21}}, -\tfrac{4}{\sqrt{21}}\right)\) |
| (B) Direction ratios of the line | (II) (4, -2, -2) |
| (C) Direction cosines of the line | (III) (1, -2, 4) |
| (D) Direction ratios of a line perpendicular to given line | (IV) (-1, 2, -4) |