Question:medium

The moment of inertia of a thin uniform rod of mass ' (M) ' and length ' (L) ', about an axis perpendicular to length and at a distance ' (L/4) ' from one end is

Show Hint

$I = \frac{ML^2}{3}$ about one end and $\frac{ML^2}{12}$ about the center.
Updated On: Apr 30, 2026
  • (\frac{ML^2}{6})
  • (\frac{ML^2}{12})
  • (\frac{7ML^2}{24})
  • [suspicious link removed]
Show Solution

The Correct Option is D

Solution and Explanation

Was this answer helpful?
0