Question:medium

The moment of inertia of a disc of mass \(m\) and radius \(R\) about an axis, which is tangential to the circumference of the disc and parallel to its diameter is

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For disc: \(I_{\text{about diameter}} = \frac{1}{4}mR^2\), \(I_{\text{about perpendicular axis through centre}} = \frac{1}{2}mR^2\).
Updated On: Apr 23, 2026
  • \(\frac{3}{2} mR^2\)
  • \(\frac{2}{3} mR^2\)
  • \(\frac{5}{4} mR^2\)
  • \(\frac{4}{5} mR^2\)
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The Correct Option is C

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