To solve this problem, we need to understand the structure of diphenylmethane and the concept of structural isomers.
Diphenylmethane has the molecular structure C_6H_5-CH_2-C_6H_5. It consists of two phenyl groups (C6H5) connected by a methylene bridge (CH2).
When one hydrogen of diphenylmethane is replaced by a chlorine atom, we have to consider the positions where this substitution can occur. The possible substitution positions are:
- On the methylene carbon (CH2 group): This substitution leads to one possible isomer.
- On the phenyl ring(s): Each phenyl ring has 5 available hydrogen positions for substitution. Given there are 2 phenyl rings, we consider symmetrical and equivalent substitutions.
Since substitution on the methylene bridge creates one unique isomer, let's focus on substitutions on the phenyl rings:
- Substitute at ortho (relative to bridge) position on any phenyl: 1 unique isomer as both rings are identical and swapping leads to the same structure.
- Substitute at meta position on any phenyl: 1 unique isomer due to ring symmetry.
- Substitute at para position on any phenyl: 1 unique isomer due to ring symmetry.
Therefore, combining these, we have the following structural isomers:
- 1 isomer with chlorine at methylene carbon.
- 1 ortho-substituted isomer on either phenyl ring.
- 1 meta-substituted isomer on either phenyl ring.
- 1 para-substituted isomer on either phenyl ring.
Summarizing the possibilities, we get a total of 4 structural isomers:
- 1 Chlorine on the methylene bridge.
- 3 positions on the phenyl rings (ortho, meta, para).
Thus, the correct answer is 4 structural isomers.
This confirms the correct option is 4.