Use the definition of molality and convert to mole fraction. Molality $2.0$ means $n_{solute}=2.0$ mol in $1000$ g water, and $n_{water}=1000/18 \approx 55.6$ mol. \[x_{solute}=\frac{2.0}{2.0+55.6}\approx\frac{2.0}{57.6}\approx 0.0347\]The value is close to $m\times M_{water}/1000 = 2.0\times18/1000=0.036$, confirming the order of magnitude. Correct option: (C) 0.0347.