Question

The molar heat capacity of rock salt at low temperature varies with temperature according to Debye's \( T^3 \) law. Thus \( C = k \frac{T^3}{\theta^3} \) where \( k = 1940 \, \text{Jmol}^{-1} \text{K}^{-1} \) and \( \theta = 281 \, \text{K} \). Calculate how much heat is required to raise the temperature of 2 moles of rock salt from 10 K to 50 K:

• A. 800 J
• B. 373 J
• C. 273 J
• D. None of these

Hint:

To calculate heat using Debye's law, use the formula for molar heat capacity and integrate over the temperature range.

Answer 1

The Correct Option is C