Question:medium
The molar conductivity \((\Lambda_{m})\) acetic acid is \(78.1 \text{S cm}^{2} \text{mol}^{-1}\) . Its degree of dissociation \((\alpha)\) is \((\Lambda_{m}^{0})\) for acetic acid= 390.5 S \(cm^{2} \text{mol}^{-1}\)
The molar conductivity \((\Lambda_{m})\) acetic acid is \(78.1 \text{S cm}^{2} \text{mol}^{-1}\) . Its degree of dissociation \((\alpha)\) is \((\Lambda_{m}^{0})\) for acetic acid= 390.5 S \(cm^{2} \text{mol}^{-1}\)
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Kohlrausch's law: \(\Lambda_m^0\) for weak electrolyte = sum of ionic conductivities of cation and anion.
Updated On: Apr 24, 2026
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- 0.04
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The Correct Option is D
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