Question:medium

The molar conductivity ($\Lambda_m^0$) at infinite dilution for HCl, NaCl and CH$_3$COONa at 25\(^{\circ}\)C are 426, 126 and 91 S cm\(^2\) respectively. The \(\Lambda_m^0\) for acetic acid at the same temperature will be

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For calculating the limiting molar conductivity of a weak electrolyte using Kohlrausch's Law, typically you add the \(\Lambda_m^0\) of two strong electrolytes whose ions, when combined and one common ion subtracted, yield the ions of the weak electrolyte. A common pattern is: $\Lambda_m^0(\text{Weak Acid}) = \Lambda_m^0(\text{Salt of Weak Acid}) + \Lambda_m^0(\text{Strong Acid}) - \Lambda_m^0(\text{Salt of Strong Acid})$.
Updated On: May 6, 2026
  • 391 S cm\(^2\)
  • 209 S cm\(^2\)
  • 461 S cm\(^2\)
  • 643 S cm\(^2\)
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The Correct Option is A

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