Question:medium

The modulus and argument of \((1+i\sqrt{3})^{8}\) are respectively...

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Write 1 + i root 3 in polar form and apply De Moivre's theorem.
Updated On: Nov 12, 2026
  • \(2\) and \(2\pi /3\)
  • \(256\) and \(7\pi /3\)
  • \(256\) and \(2\pi /3\)
  • \(64\) and \(4\pi /3\)
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The Correct Option is C

Solution and Explanation

Step 1: Modulus
The modulus of a power is the power of the modulus: $|1+i\sqrt{3}|=2$, so $|(1+i\sqrt{3})^{8}|=2^{8}=256$.

Step 2: Argument
Each factor contributes the angle $\dfrac{\pi}{3}$, so eight factors give $\dfrac{8\pi}{3}$.

Step 3: Principal value
Subtract $2\pi$: $\dfrac{8\pi}{3}-2\pi=\dfrac{2\pi}{3}$, which lies in the principal range.

Final Answer:
The modulus is 256 and the argument is 2π/3. \[ \boxed{\text{(C) }256\text{ and }2\pi /3} \]
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