Step 1: Modulus
The modulus of a power is the power of the modulus: $|1+i\sqrt{3}|=2$, so $|(1+i\sqrt{3})^{8}|=2^{8}=256$.
Step 2: Argument
Each factor contributes the angle $\dfrac{\pi}{3}$, so eight factors give $\dfrac{8\pi}{3}$.
Step 3: Principal value
Subtract $2\pi$: $\dfrac{8\pi}{3}-2\pi=\dfrac{2\pi}{3}$, which lies in the principal range.
Final Answer:
The modulus is 256 and the argument is 2π/3.
\[ \boxed{\text{(C) }256\text{ and }2\pi /3} \]