Question:medium

The minute-hand and second-hand of a clock cross each other \underline{\hspace{1cm}} times between 09:15:00 AM and 09:45:00 AM on a day.

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Minute and second hand cross each other 59 times in one hour. In 30 minutes, they cross about half, i.e. ~29 times.
Updated On: Jan 13, 2026
  • 30
  • 15
  • 29
  • 31
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The Correct Option is C

Solution and Explanation

Step 1: Hand Speeds.
- The second hand's speed is \(360^\circ/60 = 6^\circ/s\).
- The minute hand's speed is \(360^\circ/3600 = 0.1^\circ/s\).

Step 2: Relative Speed.
Relative speed of the hands is \(6 - 0.1 = 5.9^\circ/s\).

Step 3: Time Between Coincidences.
Coincidence occurs when the relative angular displacement is \(360^\circ\). \[T = \frac{360}{5.9} \approx 61.02 \, s\]

Step 4: Given Duration.
The total time from 9:15 to 9:45 is 30 minutes, which equals \(1800 \, s\).

Step 5: Number of Coincidences.
\[N = \frac{1800}{61.02} \approx 29.49\] Therefore, the hands coincide 29 times within this interval. \[\boxed{29}\]

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