Question:medium
The minimum value of $x^{2} + \dfrac{1}{1 + x^{2}}$ is at}
The minimum value of $x^{2} + \dfrac{1}{1 + x^{2}}$ is at}
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When a function involves $x^2$ throughout, substitute $t = x^2 \geq 0$ to convert it to a single-variable optimisation problem.
Updated On: Apr 8, 2026
- $x = 0$
- $x = 1$
- $x = 4$
- $x = 3$
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The Correct Option is A
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