Question:medium

The minimum radius vector of the curve \( \frac{a^2}{x^2} + \frac{b^2}{y^2} = 1 \) is of length

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For minimum distance problems, minimize $r^2$ instead of $r$ for easier calculations.
Updated On: Apr 23, 2026
  • $a - b$
  • $a + b$
  • $2a + b$
  • None of these
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The Correct Option is D

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