The mean deviation from the median for the following data is
| \( x_i \) | 2 | 9 | 8 | 3 | 5 | 7 |
|---|---|---|---|---|---|---|
| \( f_i \) | 5 | 3 | 1 | 6 | 6 | 1 |
Step 1: Understanding the Concept:
We need to calculate the Mean Deviation from the Median. This involves sorting the data, finding the cumulative frequency to identify the median, finding the absolute deviation of each observation from the median, and then computing the weighted mean of these deviations.
Step 2: Key Formula or Approach:Mean Deviation = Σ fi |xi - Median| / Σ fi
Step 3: Detailed Explanation:
First, arrange the table in ascending order of xi:
| xi | fi | Cumulative Freq (CF) |
|---|---|---|
| 2 | 5 | 5 |
| 3 | 6 | 11 |
| 5 | 6 | 17 |
| 7 | 1 | 18 |
| 8 | 1 | 19 |
| 9 | 3 | 22 |
Total observations N = Σ fi = 22.
Since N is even, the median is the average of the (N/2)th and (N/2 + 1)th terms.N/2 = 11, N/2 + 1 = 12.
From the CF column:
- The 11th term is 3.
- The 12th term falls in the next value, so it is 5.Median (M) = (3 + 5) / 2 = 4
Now, compute |xi - 4| and fi|xi - 4|:
| xi | fi | |xi - 4| | fi|xi - 4| |
|---|---|---|---|
| 2 | 5 | 2 | 10 |
| 3 | 6 | 1 | 6 |
| 5 | 6 | 1 | 6 |
| 7 | 1 | 3 | 3 |
| 8 | 1 | 4 | 4 |
| 9 | 3 | 5 | 15 |
Sum of deviations:Σ fi|xi - 4| = 10 + 6 + 6 + 3 + 4 + 15 = 44
Calculate Mean Deviation:M.D. = 44 / 22 = 2
Step 4: Final Answer:
The mean deviation is 2.
If \(S=\{1,2,....,50\}\), two numbers \(\alpha\) and \(\beta\) are selected at random find the probability that product is divisible by 3 :
The probability of hitting the target by a trained sniper is three times the probability of not hitting the target on a stormy day due to high wind speed. The sniper fired two shots on the target on a stormy day when wind speed was very high. Find the probability that
(i) target is hit.
(ii) at least one shot misses the target. 