The mean deviation from the median for the following data is
| \( x_i \) | 2 | 9 | 8 | 3 | 5 | 7 |
|---|---|---|---|---|---|---|
| \( f_i \) | 5 | 3 | 1 | 6 | 6 | 1 |
Step 1: Understanding the Concept:
We need to calculate the Mean Deviation from the Median. This involves sorting the data, finding the cumulative frequency to identify the median, finding the absolute deviation of each observation from the median, and then computing the weighted mean of these deviations.
Step 2: Key Formula or Approach:Mean Deviation = Σ fi |xi - Median| / Σ fi
Step 3: Detailed Explanation:
First, arrange the table in ascending order of xi:
| xi | fi | Cumulative Freq (CF) |
|---|---|---|
| 2 | 5 | 5 |
| 3 | 6 | 11 |
| 5 | 6 | 17 |
| 7 | 1 | 18 |
| 8 | 1 | 19 |
| 9 | 3 | 22 |
Total observations N = Σ fi = 22.
Since N is even, the median is the average of the (N/2)th and (N/2 + 1)th terms.N/2 = 11, N/2 + 1 = 12.
From the CF column:
- The 11th term is 3.
- The 12th term falls in the next value, so it is 5.Median (M) = (3 + 5) / 2 = 4
Now, compute |xi - 4| and fi|xi - 4|:
| xi | fi | |xi - 4| | fi|xi - 4| |
|---|---|---|---|
| 2 | 5 | 2 | 10 |
| 3 | 6 | 1 | 6 |
| 5 | 6 | 1 | 6 |
| 7 | 1 | 3 | 3 |
| 8 | 1 | 4 | 4 |
| 9 | 3 | 5 | 15 |
Sum of deviations:Σ fi|xi - 4| = 10 + 6 + 6 + 3 + 4 + 15 = 44
Calculate Mean Deviation:M.D. = 44 / 22 = 2
Step 4: Final Answer:
The mean deviation is 2.