Question:medium

The maximum number of RBr producing 2-methylbutane by above sequence is _____________.
RBr 2 methylbutane

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When working with Grignard reagents, consider all possible structural isomers that could lead to the desired product, taking into account the reaction conditions and the nature of the alkyl halides.
Updated On: Jan 14, 2026
  • 3
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The Correct Option is A

Solution and Explanation

The reaction proceeds via the formation of a Grignard reagent from alkyl halide (RBr) and magnesium in dry ether, followed by reaction with water to yield 2-methylbutane.

When considering structural isomers of RBr, a maximum of 3 isomers can lead to the formation of 2-methylbutane through this reaction.

The RBr isomers capable of producing 2-methylbutane are:

  • 1-Bromo-3-methylbutane
  • 2-Bromo-2-methylbutane
  • 3-Bromo-2-methylbutane

Therefore, the maximum count of RBr isomers yielding 2-methylbutane is 3.

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