Question:medium

The maximum kinetic energy of a proton ejected from a cyclotron with dees of radius \(70\) cm and oscillating frequency \(5\) MHz (in MeV) is \[ (\text{Mass of proton}=1.67\times10^{-27}\text{ kg}) \]

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For a cyclotron, \[ \boxed{ K_{\max} = \frac12m(2\pi fr)^2. } \] After obtaining energy in joules, convert it to MeV using \[ \boxed{ 1\text{ MeV}=1.6\times10^{-13}\text{ J}. } \]
Updated On: Jul 18, 2026
  • \(2.53\)
  • \(3.87\)
  • \(1.46\)
  • \(4.84\)
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The Correct Option is A

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