Step 1: First reagent.
TiCl$_3$ with Zn-Cu is a McMurry coupling, which joins two carbonyl groups into an alkene.
Step 2: Product M.
Two molecules of acetophenone couple to give the more stable trans alkene, trans-2,3-diphenyl-2-butene.
Step 3: Reaction with bromine.
Bromine adds across the double bond in an anti fashion.
Step 4: Product N.
Anti addition to the trans alkene gives the meso dibromide.
Step 5: Answer.
\[ \boxed{\text{D}} \]