To determine the major product (P) of the given reaction, let's analyze the reaction step by step.
The given compound is a tertiary alcohol, which is prone to undergoing an acid-catalyzed dehydration reaction when treated with an acid (H+).
Mechanism of Reaction:
The hydroxyl group (OH) in the tertiary alcohol is protonated by the acid (H+), forming a good leaving group (water molecule).
After the loss of water, a carbocation intermediate is formed. In this case, the carbocation is tertiary, which is relatively stable.
To form the most stable product, a methyl shift occurs. This rearrangement can lead to a more stable carbocation due to hyperconjugation and inductive effects.
The final step involves the elimination of a proton (H+) to form the double bond, resulting in the formation of an alkene.
Given this mechanism, the double bond will form at the most substituted position, following Saytzeff's rule, which states that the more substituted alkene is generally the more stable and major product.
Based on the presented options, the major product of this reaction will have the double bond between the most substituted adjacent carbons.
Major Product
Conclusion:
The correct major product (P) of this reaction is the one shown above, which corresponds to the option with the data-src-id "65b38421be7f7559498569a4". It follows from the mechanism of acid-catalyzed dehydration of the tertiary alcohol and the formation of the most stable alkene based on carbocation rearrangement and elimination.
