To determine which statements correctly apply to chlorobenzene as compared to chlorocyclohexane, let's examine each statement:
In chlorobenzene, due to resonance, the lone pair of electrons on chlorine is delocalized into the benzene ring, thereby reducing the negative charge localized on the chlorine atom itself. On the other hand, in chlorocyclohexane, no resonance stabilizes or delocalizes the lone pair of electrons, which means more negative charge remains on the chlorine atom. Thus, this statement is correct.
In chlorobenzene, the C--Cl bond exhibits partial double bond character because of resonance. The lone pair of electrons on the chlorine atom overlaps with the π-electrons of the benzene ring, creating a double bond-like character. This statement is correct for chlorobenzene.
In chlorobenzene, due to the resonance and partial double bond character of the C--Cl bond, the bond is less polar compared to chlorocyclohexane, where the C--Cl bond is purely single and thus more polar. This statement is true for chlorobenzene.
Actually, due to the partial double bond character in chlorobenzene, the C--Cl bond is shorter compared to chlorocyclohexane which has a pure single bond. Thus, this statement is incorrect.
In chlorobenzene, the carbon atom is sp^2 hybridized due to its bonding in the aromatic ring. This results in forming the C--Cl bond using an sp^2 hybridised orbital. This statement is correct.
Given the analysis:
Hence, the answer is: A, D and E Only
Arrange the following alkenes in the decreasing order of stability:
Choose the correct answer from the options given below:
The reactions which cannot be applied to prepare an alkene by elimination, are
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