Question:medium

The major product P formed in the following transformation is

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MnO$_2$ selectively oxidizes benzylic alcohols, PBr$_3$ converts alcohols into bromides, and base then gives elimination to form the conjugated enone
Updated On: Jun 1, 2026
  • A
  • B
  • C
  • D
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The Correct Option is A

Solution and Explanation

Step 1: Selective oxidation.
Manganese dioxide oxidises only the benzylic alcohol to a ketone and leaves the primary alcohol untouched.

Step 2: Make the bromide.
Phosphorus tribromide turns the remaining primary alcohol into a primary bromide.

Step 3: Base induced elimination.
Sodium ethoxide removes an alpha hydrogen and eliminates bromide to give a conjugated enone.

Step 4: Answer.
\[ \boxed{\text{A}} \]
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