Question

The major product obtained in the following reaction is

Choose the correct answer from the options given below

• A. 4-Iodo-4-methylhexane
• B. 4-Iodo-3-methylhexane
• C. 3-Iodo-3-methylhexane
• D. 3-Iodo-4-methylhexane

Hint:

When applying Markovnikov's rule to highly substituted alkenes, the halogen atom always ends up attached to the more highly substituted carbon of the original double bond because it hosts the more stable carbocation.

Answer 1

The Correct Option is C

Step 1: Understanding the Question:
The question requires predicting the major product and its IUPAC name for the addition of HI to 3-methylhex-3-ene.

Step 2: Key Formula or Approach:
The electrophilic addition follows Markovnikov's rule, where H⁺ attaches to the less substituted carbon to generate the more stable tertiary carbocation intermediate.

Step 3: Detailed Explanation:
Protonation at C-4 of 3-methylhex-3-ene creates a stable 3° carbocation at C-3. The iodide ion (I⁻) then attacks this carbocation, resulting in the product 3-iodo-3-methylhexane.

Step 4: Final Answer:
The major product is 3-Iodo-3-methylhexane, which corresponds to option (C).