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The line $x + y = 2$ touches a circle. If the centre of the circle is at $(-4,\,0)$, then the radius of the circle is
The line $x + y = 2$ touches a circle. If the centre of the circle is at $(-4,\,0)$, then the radius of the circle is
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The perpendicular distance from point $(x_0,y_0)$ to line $ax+by+c=0$ is $\dfrac{|ax_0+by_0+c|}{\sqrt{a^2+b^2}}$. This equals the radius when the line is tangent to the circle.
Updated On: Apr 25, 2026
- $2\sqrt{2}$
- $\dfrac{3\sqrt{2}}{2}$
- $\sqrt{2}$
- $\dfrac{\sqrt{2}}{2}$
- $3\sqrt{2}$
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The Correct Option is
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