Question:medium

The limiting molar conductance for aqueous solution of CaCl\(_2\) at 298K is 271.6 S cm\(^2\) mol\(^{-1}\). If the limiting ionic conductance of Ca\(^{2+}\) ion at the same temperature is 119 S cm\(^2\) mol\(^{-1}\) what is the limiting ionic conductance of Cl\(^-\) ion?

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A common mistake is forgetting the factor of 2 for the Chloride ions.
Always write the balanced dissociation equation first: \(CaCl_2 \to Ca^{2+} + 2Cl^-\).
Updated On: Apr 29, 2026
  • 152.6 S cm\(^2\) mol\(^{-1}\)
  • 76.3 S cm\(^2\) mol\(^{-1}\)
  • 135.8 S cm\(^2\) mol\(^{-1}\)
  • 228.7 S cm\(^2\) mol\(^{-1}\)
  • 114.35 S cm\(^2\) mol\(^{-1}\)
Show Solution

The Correct Option is B

Solution and Explanation

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