The length of the tangent from the point \((5,1)\) to the circle \(x^2+y^2+6x-4y-3=0\) is
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For a circle \(S=0\), the tangent length from a point \((x_1,y_1)\) is \(\sqrt{S_1}\), where \(S_1\) is obtained by substituting the point in the circle equation.