Question:medium
The length of the tangent drawn from any point on the circle \( x^2 + y^2 + 2\lambda x + \mu = 0 \) to the circle \( x^2 + y^2 + 2\gamma x + \lambda = 0 \), where \( \mu \geq \lambda \), is:
The length of the tangent drawn from any point on the circle \( x^2 + y^2 + 2\lambda x + \mu = 0 \) to the circle \( x^2 + y^2 + 2\gamma x + \lambda = 0 \), where \( \mu \geq \lambda \), is:
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To find the length of the tangent from a point to a circle, use the formula involving the radius and the distance from the center.
Updated On: Mar 25, 2026
- \( \sqrt{\mu - \lambda} \)
- \( \sqrt{\mu^2 - \lambda^2} \)
- \( \sqrt{\mu - \lambda^2} \)
- \( \mu + \lambda \)
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The Correct Option is A
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