Question:medium

The length of the common chord of the circles \[ x^2+y^2-8x-6y-11=0 \] and \[ x^2+y^2-6x+8y+9=0 \] is

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The common chord of two circles is their radical axis. Its length is \[ \boxed{2\sqrt{r^2-d^2}}, \] where \(d\) is the perpendicular distance from the centre to the radical axis.
Updated On: Jul 18, 2026
  • \(\sqrt{42}\)
  • \(7\)
  • \(\dfrac{13}{2}\)
  • \(\sqrt{46}\)
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The Correct Option is D

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