Question:medium

The electronegativity of the Silicon (Si) atom using Allred-Rochow scale of electronegativity is. Given: The covalent radius for Si atom = 1.175 Angstrom.

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The Allred-Rochow electronegativity scale uses the covalent radius to determine the electronegativity of an atom.
Updated On: Feb 10, 2026
  • 2.40
  • 2.50
  • 2.20
  • 2.10
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The Correct Option is C

Solution and Explanation

Step 1: Allred-Rochow Electronegativity Formula. The Allred-Rochow electronegativity (\( \chi \)) is calculated using the formula: \[\chi = \frac{0.359}{r} + 0.744\] where \( r \) represents the covalent radius in Angstroms.

Step 2: Apply the Formula for Si. For Silicon (Si), the covalent radius \( r = 1.175 \, \text{Å} \). Substituting this value into the formula yields: \[\chi = \frac{0.359}{1.175} + 0.744 = 0.305 + 0.744 = 2.20\]

Step 3: Conclusion. Consequently, the electronegativity of Silicon (Si) is determined to be 2.20, which aligns with option (3).

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