Question:medium

The ionisation constant of the weak acid HF whose concentration is 0.1 M is \( 3.5 \times 10^{-4} \). The equilibrium constant value for the reaction
\[ \text{F}^- + \text{H}_2\text{O} \leftrightarrow \text{HF} + \text{OH}^- \]
is ............ and the pH of the aqueous solution of the weak acid is ...............

Show Hint

When dealing with weak acid dissociation and equilibrium constants, remember that the dissociation of water and the conjugate base affect the equilibrium. Also, the pH can be calculated from the \( [\text{H}^+] \) concentration using \( \text{pH} = -\log [\text{H}^+] \).
Updated On: May 5, 2026
  • \( K_{\text{eq}} = 4.4 \times 10^{-11} \quad \text{pH} = 4.25 \)
  • \( K_{\text{eq}} = 3.58 \times 10^{-11} \quad \text{pH} = 4.19 \)
  • \( K_{\text{eq}} = 2.86 \times 10^{-11} \quad \text{pH} = 3.23 \)
  • \( K_{\text{eq}} = 3.92 \times 10^{-10} \quad \text{pH} = 4.07 \)
Show Solution

The Correct Option is C

Solution and Explanation

Was this answer helpful?
0