Question:medium

The integral \( \int e^x \left(\tan^{-1}x + \frac{1}{1+x^2}\right) dx \) is equal to

Show Hint

Always look for the pattern \( \int e^x (f(x) + f'(x)) dx \) when you see an \( e^x \) multiplied by a sum of functions. Identifying \( f(x) \) and its derivative \( f'(x) \) simplifies the integral significantly.
Updated On: May 15, 2026
  • \( e^x (\tan^{-1}x + 2) + C \)
  • \( \tan^{-1}x + C \)
  • \( e^x \tan^{-1}x + C \)
  • \( e^x \cot^{-1}x + C \)
Show Solution

The Correct Option is C

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