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List of top Mathematics Questions on Indefinite Integrals asked in CUET (UG)
Match the
LIST-I
with
LIST-II
LIST-I
Indefinite Integral
LIST-II
Solution (where \(c\) is an arbitrary constant)
A. \(\int\sqrt{16-x^2}\,dx\)
I. \(\sin^{-1}\left(\frac{x}{4}\right)+c\)
B. \(\int\frac{dx}{\sqrt{16-x^2}}\)
II. \(\frac{x}{2}\sqrt{16-x^2}+8\sin^{-1}\left(\frac{x}{4}\right)+c\)
C. \(\int\frac{dx}{\sqrt{x^2-16}}\)
III. \(\frac{1}{8}\log\left|\frac{4+x}{4-x}\right|+c\)
D. \(\int\frac{dx}{16-x^2}\)
IV. \(\log\left|x+\sqrt{x^2-16}\right|+c\)
Choose the
correct
answer from the options given below:
CUET (UG) - 2026
CUET (UG)
Mathematics
Indefinite Integrals
Find the value of: \[ \int \frac{1}{x} \, dx \]
CUET (UG) - 2026
CUET (UG)
Mathematics
Indefinite Integrals
Evaluate: \[ \int (3x^2 + 4x - 5) \, dx \]
CUET (UG) - 2026
CUET (UG)
Mathematics
Indefinite Integrals
Evaluate the indefinite integral using pattern-based substitution: \[ \int \frac{\ln x - 1}{(\ln x)^2}\,dx \]
CUET (UG) - 2026
CUET (UG)
Mathematics
Indefinite Integrals
Evaluate the indefinite integral: \( \int \frac{x^2+1}{x^4+1}\,dx \)
CUET (UG) - 2026
CUET (UG)
Mathematics
Indefinite Integrals
The integral \( \int e^x \left(\tan^{-1}x + \frac{1}{1+x^2}\right) dx \) is equal to
CUET (UG) - 2026
CUET (UG)
Mathematics
Indefinite Integrals
The integral \( \int \frac{2+x^4}{1+x^2} dx \) is equal to
CUET (UG) - 2026
CUET (UG)
Mathematics
Indefinite Integrals
The integral I = $\int \frac{e^{5\log_e x} - e^{4\log_e x}}{e^{3\log_e x} - e^{2\log_e x}} dx$ is equal to
CUET (UG) - 2025
CUET (UG)
Mathematics
Indefinite Integrals
If \(\int \frac{(1 + x \log x)}{xe^{-x}} dx = e^x f(x) + C\), where C is constant of integration, then f(x) is
CUET (UG) - 2025
CUET (UG)
Mathematics
Indefinite Integrals
The integral I = $\int e^x (\frac{x-1}{3x^2}) dx$ is equal to
CUET (UG) - 2025
CUET (UG)
Mathematics
Indefinite Integrals
The integral I = $\int \frac{e^{5\log_e x} - e^{4\log_e x}}{e^{3\log_e x} - e^{2\log_e x}} dx$ is equal to
CUET (UG) - 2025
CUET (UG)
Mathematics
Indefinite Integrals
The integral I = $\int e^x (\frac{x-1}{3x^2}) dx$ is equal to
CUET (UG) - 2025
CUET (UG)
Mathematics
Indefinite Integrals
If \(\int \frac{(1 + x \log x)}{xe^{-x}} dx = e^x f(x) + C\), where C is constant of integration, then f(x) is
CUET (UG) - 2025
CUET (UG)
Mathematics
Indefinite Integrals