For first order reaction, rate constant at $27^{\circ} C$ and $t^{\circ} C$ are $1.5 \times 10^3$ and $4.5 \times 10^3$ respectively. If activation energy of the reaction is $60 \text{ kJmol}^{-1}$, then ($R = 8.3 \text{ Jmol}^{-1}K^{-1}$) $\ln 3 = 1.1$
Find temperature 't' (in $^{\circ} C$).