Question:medium
The hybridization involved in the central atom of \(PCl_5\) is
The hybridization involved in the central atom of \(PCl_5\) is
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Count the total number of bonds. \(P\) is bonded to 5 \(Cl\) atoms.
To accommodate 5 bonds, we need 5 hybrid orbitals.
Order of orbitals: \(s(1) + p(3) + d(1) = 5\). Thus, \(sp^3d\).
To accommodate 5 bonds, we need 5 hybrid orbitals.
Order of orbitals: \(s(1) + p(3) + d(1) = 5\). Thus, \(sp^3d\).
Updated On: Apr 29, 2026
- \(dsp^3\)
- \(sp^3d^2\)
- \(sp^2d^2\)
- \(d^2sp^3\)
- \(sp^3d\)
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The Correct Option is
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