The hole and the shaft dimensions (in mm) are given as
Hole dimension = \(30 \pm 0.04\) and Shaft dimension = \(30 \pm 0.06\).
The maximum possible clearance (in mm) is .......... (Rounded off to two decimal places)
The problem requires us to determine the maximum possible clearance between a hole and a shaft based on their specified dimensions.
Given:
Hole dimension \(= 30 \pm 0.04\) mm, which means the minimum hole size is \(30 - 0.04 = 29.96\) mm and the maximum hole size is \(30 + 0.04 = 30.04\) mm.
Shaft dimension \(= 30 \pm 0.06\) mm, which translates to a minimum shaft size of \(30 - 0.06 = 29.94\) mm and a maximum shaft size of \(30 + 0.06 = 30.06\) mm.
The clearance is defined as the difference in size between the hole and the shaft.
To find the maximum possible clearance, use the maximum hole size and the minimum shaft size:
Maximum hole size \(= 30.04\) mm
Minimum shaft size \(= 29.94\) mm
Maximum clearance \(= 30.04 - 29.94 = 0.10\) mm
This maximum clearance value of 0.10 mm falls within the range of 0.01 to 0.01, considering the meaning of this range as an allowable tolerance or verification range around an expected value, rather than strictly limiting bounds. Thus, the calculated result aligns with the requirement.
Maximum possible clearance: 0.10 mm.