A company purchases items in bulk for getting quantity discounts in the item’s price. The price break-up is given in the table. The annual demand for the item is 5000 units. The ordering cost is Rupees 400 per order. The annual inventory carrying cost is 30 percent of the purchase price per unit. The optimal order size (in units) is .......... (Answer in integer) 
The optimal order size, or Economic Order Quantity (EOQ), is determined using the EOQ formula: EOQ = \sqrt{\frac{2DS}{H}}, where D is the annual demand, S the ordering cost, and H the holding cost per unit.
Given:
Annual demand (D) = 5000 units
Ordering cost (S) = ₹400
Annual inventory carrying cost = 30% of unit price
For each price bracket, calculate EOQ and cost:
\sqrt{\frac{2*5000*400}{3}} = \sqrt{1333333.33} ≈ 1155\sqrt{\frac{2*5000*400}{2.4}} = \sqrt{1666666.67} ≈ 1291\sqrt{\frac{2*5000*400}{2.1}} = \sqrt{1904761.90} ≈ 1379The EOQ must be in the range of each price bracket for optimal cost:
Verify: The computed optimal order size 1291 falls within its respective price range of 1200 ≤ Q < 2000.
Thus, the optimal order size is 1291 units, which is within the specified range 1995,1995.
The zero line of the Vernier scale lies between divisions 20 and 21 of the main scale. The 4th Vernier scale division exactly coincides with a main scale division. The 5 divisions of the Vernier scale are equal to 4 divisions of the main scale. If one main scale division is 1 mm, the measured value (in mm) is ........... (Rounded off to one decimal place)}
Three plants P1, P2, and P3 produce 6, 1, and 9 thousand liters of fruit juice, respectively. The produced fruit juice is transported to three distribution centers D1, D2, and D3 with a requirement of 7, 5, and 4 thousand liters of juice, respectively. The transportation cost (in hundreds of Rupees) from each plant to each distribution center is given in the table. The total transportation cost (in hundreds of Rupees) in the initial basic feasible solution using Vogel’s approximation method is ............. (Answer in integer) 
A steel plate is fastened to a channel using three identical bolts as shown in the figure. The bolts are made of carbon steel of permissible yield strength in shear as 400 N/mm². The plate is subjected to a force of 12 kN. Neglect the weight of the plate. The magnitude of the resultant shear force (in N) on bolt 2 is ............. (Answer in integer) 