For line-of-sight calculations, use the approximate formula d = √2Rh.
To determine the area up to which the antenna will transmit the signal, we need to calculate the area of the circle on the surface of the Earth that the antenna can cover. This is done using the formula:
\(A = \pi \cdot d^2\)
Where \(d\) is the distance from the top of the antenna to the horizon as seen from that point.
The distance \(d\) can be found using the formula:
\(d = \sqrt{2 \cdot h \cdot R}\)
Where:
Let's calculate \(d\):
\(d = \sqrt{2 \cdot 0.098 \cdot 6400}\)
\(d = \sqrt{1254.4}\)
\(d \approx 35.41 \, \text{km}\)
Now, we calculate the area \(A\) up to which the signal will transmit:
\(A = \pi \cdot (35.41)^2\)
\(A \approx 3.1416 \cdot 1254.4881\)
\(A \approx 3942 \, \text{km}^2\)
Therefore, the area up to which the antenna will transmit the signal is approximately \(3942 \, \text{km}^2\), which matches the provided correct answer.
Match List-I with List-II:
| List-I (Modulation Schemes) | List-II (Wave Expressions) |
|---|---|
| (A) Amplitude Modulation | (I) \( x(t) = A\cos(\omega_c t + k m(t)) \) |
| (B) Phase Modulation | (II) \( x(t) = A\cos(\omega_c t + k \int m(t)dt) \) |
| (C) Frequency Modulation | (III) \( x(t) = A + m(t)\cos(\omega_c t) \) |
| (D) DSB-SC Modulation | (IV) \( x(t) = m(t)\cos(\omega_c t) \) |
Choose the correct answer: