Question

The graph shows the variation of voltage (v) across the plates of two parallel plate capacitors $A$ and $B$ versus increase of charge $Q$ stored in them. Then

• A. capacity of both capacitors is same.
• B. capacity of $A$ is higher than $B$.
• C. capacity of $B$ is higher than $A$.
• D. capacity of both is zero.

Hint:

In a \(V\)-vs-\(Q\) graph: \[ \text{slope}=\frac{1}{C} \] So smaller slope means larger capacitance.

Answer 1

The Correct Option is C

Step 1: Understanding the Concept:
Capacitance is the charge stored per unit potential difference. It is the reciprocal of the slope in a $V$ vs $Q$ graph.
Step 2: Key Formula or Approach:
$C = Q / V$.
Step 3: Detailed Explanation:
For a constant $V$, capacitor $A$ stores more charge $Q$ than capacitor $B$. Since $C = Q/V$, a larger $Q$ for the same $V$ implies a higher $C$. Thus, $C_A>C_B$.
Step 4: Final Answer:
Capacity of $A$ is higher than $B$.