List of top Physics Questions on Capacitance asked in MHT CET

A parallel plate air capacitor having area of each plate '\(A\)' and the distance between the plates '\(d\)' has uniform electric field E in the space between the plates. The energy stored in the capacitor is (\(ε_0\) = permittivity of free space.)

A slab of material of dielectric constant \(K\) has the same area as the plates of a parallel plate capacitor but has a thickness \((4/5)d\), where \(d\) is the separation of the plates. The capacitance in the presence and absence of dielectric are \(C\) and \(C_0\) respectively. The ratio \((C/C_0)\) is

Two circular plates each of radius '\(r\)' are kept parallel to each other distance '\(d\)' apart. The capacitance of the capacitor formed is '\(C_1\)'. If the radius of each of the plates is increased to \(\sqrt{3}\) times the earlier radius and their distance of separation decreased to half the initial value, the capacitance now becomes '\(C_2\)'. The ratio \(C_1:C_2\) is

A parallel plate capacitor with air between the plate has a capacitance of \(15\) pF. The separation between the plates becomes twice and the space between them is filled with a medium of dielectric constant \(3.5\). Then the capacitance becomes \(x/4\) pF.
The value of \(x\) is

The earth is assumed to be a charged conducting sphere having volume 'V' and surface area 'A'. The capacitance of the earth in free space is (\(ε_0\) = permittivity of free space)

The function of a dielectric in a capacitor is

The graph shows the variation of voltage (v) across the plates of two parallel plate capacitors $A$ and $B$ versus increase of charge $Q$ stored in them. Then

In between the plates of parallel plate capacitor of plate separation '$d$' a dielectric plate of thickness '$t$' is inserted. The capacitance becomes one-third of the original capacity without dielectric. The dielectric constant of the plate is

An air filled parallel plate capacitor has a capacity \(2\ \text{pF}\). The separation of the plates is doubled and the interspace between the plates is filled with dielectric material, then the capacity is increased to \(6\ \text{pF}\). The dielectric constant of the material is

A parallel plate air capacitor is charged upto $100\ \text{V}$. A plate $2\ \text{mm}$ thick is inserted between the plates. Then to maintain the same potential difference, the distance between the plates is increased by $1.6\ \text{mm}$. The dielectric constant of the thick plate is

A parallel plate capacitor filled with oil of a dielectric constant 3 between the plates has capacitance 'C'. If the oil is removed, then the capacitance of the capacitor will be

In between the plates of parallel plate capacitor of plate separation '$d$' a dielectric plate of thickness '$t$' is inserted. The capacitance becomes one-third of the original capacity without dielectric. The dielectric constant of the plate is