Question:medium

The graph of an inverse trigonometric function passes through the point $(0, \frac{\pi}{2})$ with asymptotes at $y = 0$ and $y = \pi$. This graph represents the function:

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Always check the domain and boundaries (y-intercepts and asymptotes) of the basic inverse trigonometric functions: - \(\tan^{-1}(0) = 0\) - \(\cot^{-1}(0) = \frac{\pi}{2}\) - \(\sec^{-1}(x)\) and \(\csc^{-1}(x)\) are undefined at \(x = 0\).
  • \(y = \sec^{-1} x\)
  • \(y = \cot^{-1} x\)
  • \(y = \tan^{-1} x\)
  • \(y = \csc^{-1} x\)
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The Correct Option is B

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