Question:medium

The general solution of the differential equation $\frac{dy}{dx} + (\sec x \csc x)y = \cos^2 x$ is

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To solve a linear differential equation $\frac{dy}{dx}+P(x)y=Q(x)$, first calculate the integrating factor $I(x) = e^{\int P(x)dx}$. The general solution is then given by the formula $y \cdot I(x) = \int Q(x) \cdot I(x) dx + C$.
Updated On: Mar 30, 2026
  • $y \sec^2 x = \sin^2 x + c$
  • $y \sec^2 x = \tan x + c$
  • $y \tan x = \sin x \cos x + c$
  • $2y \tan x = \sin^2 x + c$
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The Correct Option is D

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