Question:medium

The function $x^x$ is increasing, when

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For $x^x$, derivative is $x^x(\ln x + 1)$—remember this shortcut.
Updated On: Apr 23, 2026
  • $x>\frac{1}{e}$
  • $x<\frac{1}{e}$
  • $x<0$
  • for all $x$
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The Correct Option is A

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