Question:medium
The function f(x)=x-|x-x²|,-1≤ x\le1 is
The function f(x)=x-|x-x²|,-1≤ x\le1 is
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Absolute value functions are often continuous but fail differentiability at sign-change points.
Updated On: Mar 19, 2026
- [-1,1]
- (-1,1)
- [-1,1] but not differentiable at 0
- (-1,1)setminus0
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The Correct Option is C
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