Question

The frequency of a given a.c. signal is 'N' Hz. When it is connected to a half wave rectifier, the number of output pulses given by the rectifier in 1 second is

• A. $\frac{N}{4}$
• B. $\frac{N}{2}$
• C. $N$
• D. $2N$

Hint:

Remember the rectifier frequency rules: * **Half-Wave Rectifier:** Output frequency = Input frequency ($f_{\text{out}} = f_{\text{in}}$) * **Full-Wave Rectifier:** Output frequency = $2 \times$ Input frequency ($f_{\text{out}} = 2f_{\text{in}}$) Since this is a half-wave setup, the count maps directly to $N$!

Answer 1

The Correct Option is C

Step 1: Count the input cycles.
An AC signal of $N$ Hz completes $N$ full cycles each second. Each cycle has one positive and one negative half.

Step 2: See what a half-wave rectifier does.
It passes only one half of each cycle and blocks the other. So each input cycle gives exactly one output pulse.

Step 3: Total pulses.
With $N$ cycles per second, there are $N$ pulses per second. \[ \boxed{N} \]