Question:medium
The formation of \( \mathrm{O}_{2}^{+}[\mathrm{PtF}_{6}]^{-} \) is the basis for the formation of xenon fluorides because:
The formation of \( \mathrm{O}_{2}^{+}[\mathrm{PtF}_{6}]^{-} \) is the basis for the formation of xenon fluorides because:
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Xenon chemistry started when its I.E. was found to match Oxygen's I.E.
Updated On: Apr 8, 2026
- $O_{2}$ and $Xe$ have comparable sizes
- Both $O_{2}$ and $Xe$ are gases
- $O_{2}$ and $Xe$ have comparable ionisation energies
- Both (A) and (C)
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The Correct Option is D
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