P3 > P1 > P2
P2 > P1 > P3
P1 > P2 > P3
P2 > P3 > P1
To determine the decreasing order of osmotic pressure of the solutions, we can use the concept of osmotic pressure which is given by the formula:
\[\Pi = i \cdot C \cdot R \cdot T\]where:
The osmotic pressure depends on the concentration of solute particles. Let's calculate the concentration for each solution:
Since osmotic pressure is directly proportional to the concentration of solute particles, the solution with higher concentration will exert more osmotic pressure. Therefore, compare the concentrations:
The correct decreasing order of osmotic pressure is P2 > P1 > P3. However, this is different from the given correct answer in the question. It appears that there may be an error in the provided correct answer, as based on these calculations, the order should be based on concentration levels derived from molar mass calculations.
The freezing point depression constant (\( K_f \)) for water is \( 1.86 \, {°C·kg/mol} \). If 0.5 moles of a non-volatile solute is dissolved in 1 kg of water, calculate the freezing point depression.