Question:medium

The following compound which cannot be prepared by Wurtz reaction is

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Wurtz reaction typically gives alkanes with an even number of carbon atoms when a single alkyl halide is used. Methane (C1) is impossible to obtain.
Updated On: May 24, 2026
  • Methane
  • Ethane
  • Butane
  • Propane
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The Correct Option is A

Solution and Explanation

The Wurtz reaction is a coupling reaction used in organic chemistry to synthesize alkanes. In this reaction, alkyl halides are reacted with sodium metal in dry ether to form higher alkanes. The general formula for the reaction is:

\[\text{2 R-X + 2 Na} \rightarrow \text{R-R + 2 NaX}\]

where \(R\) is the alkyl group and \(X\) is the halogen.

Let's analyze the given options to determine which compound cannot be prepared using the Wurtz reaction:

  1. Methane: Methane cannot be formed by the Wurtz reaction because only symmetrical higher alkanes can be formed by this method. The smallest alkane that can be synthesized is ethane, using the reaction of methyl halide.
  2. Ethane: Ethane can be prepared by reacting methyl chloride with sodium metal. 
     
\[\text{2 CH}_3\text{Cl} + 2 \text{Na} \rightarrow \text{CH}_3\text{-CH}_3 + 2 \text{NaCl}\]
  1. Butane: Butane can be synthesized using ethyl halide in the Wurtz reaction. 
     
\[\text{2 C}_2\text{H}_5\text{Cl} + 2 \text{Na} \rightarrow \text{C}_4\text{H}_{10} + 2 \text{NaCl}\]
  1. Propane: Propane cannot be directly synthesized using the Wurtz reaction, as it requires different alkyl halides, which results in a mixture of products. The direct synthesis of propane using Wurtz reaction is not possible.

Therefore, out of the given options, methane is the compound that cannot be prepared by the Wurtz reaction. The Wurtz reaction is efficient for synthesizing higher alkanes but not for forming the simplest alkane, which is methane.

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