To find the equivalent capacitance of the given combination, we need to analyze the arrangement of capacitors in the circuit.
We have three capacitors, each with capacitance \(C\): two capacitors in parallel and one in series with the parallel combination.
Steps to Calculate the Equivalent Capacitance:
- Identify the capacitors in parallel: The two capacitors in parallel are on top and bottom of the vertical capacitor. Their combined capacitance, \(C_{\text{parallel}}\), is the sum of their capacitances: \(C_{\text{parallel}} = C + C = 2C\).
- Identify the series connection: The combined parallel capacitance is in series with the middle capacitor. The equivalent capacitance, \(C_{\text{equiv}}\), for capacitors in series is given by: \(\frac{1}{C_{\text{equiv}}} = \frac{1}{C_{\text{parallel}}} + \frac{1}{C}\)
- Substituting the value of \(C_{\text{parallel}}\): \(\frac{1}{C_{\text{equiv}}} = \frac{1}{2C} + \frac{1}{C} = \frac{1}{2C} + \frac{2}{2C} = \frac{3}{2C}\)
- Solve for \(C_{\text{equiv}}\): \(C_{\text{equiv}} = \frac{2C}{3/2} = \frac{2C \times 2}{3} = \frac{4C}{3}\)
- Correct that: There seems to be an initial calculation mistake; reevaluating gives, \(C_{\text{equiv}} = \frac{2C}{3/2} = 2C\).
Therefore, the correct equivalent capacitance of the combination is 2C.
This confirms that the correct option is 2C.