Question:medium

The equilibrium pressure for the reaction MSO\(_4\cdot 2\)H\(_2\)O(s) \( \rightleftharpoons \) MSO\(_4\)(s) + 2H\(_2\)O(g) is \( \frac{\pi}{4} \) atm at 400 K. The \( K_p \) for the given reaction (in atm\(^2\)) is

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In heterogeneous equilibrium, solids are ignored in $K_p$.
Updated On: May 2, 2026
  • $\frac{\pi^2}{4}$
  • $\frac{\pi}{6}$
  • $\frac{\pi^2}{16}$
  • $\frac{\pi}{16}$
  • $\frac{16}{\pi}$
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The Correct Option is C

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