Question:medium
The equilibrium constant for the reaction, N$_2$(g) + 3H$_2$ $\rightleftharpoons$ 2NH$_3$(g) and 2N$_2$(g) + 6H$_2$ $\rightleftharpoons$ 4NH$_3$(g) are $K_1$ and $K_2$, respectively. The relationship between $K_1$ and $K_2$ is
The equilibrium constant for the reaction, N$_2$(g) + 3H$_2$ $\rightleftharpoons$ 2NH$_3$(g) and 2N$_2$(g) + 6H$_2$ $\rightleftharpoons$ 4NH$_3$(g) are $K_1$ and $K_2$, respectively. The relationship between $K_1$ and $K_2$ is
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If you reverse a reaction, the new equilibrium constant is $1/K$. If you multiply a reaction by $n$, the constant becomes $K^n$.
Updated On: May 1, 2026
- $K_2 = K_1^2$
- $K_2 = K_1^{-2}$
- $K_1 = K_2^2$
- $K_2 = \sqrt{K_1}$
- $K_1 = \sqrt{K_2}$
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The Correct Option is A
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