Question:medium

The equation $|z + 1 - i| = |z - 1 + i|$ represents a (where z is a complex number)

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$|z - a| = |z - b|$ is the set of points equidistant from $a$ and $b$. If $a = -b$, the line always passes through the origin.
Updated On: May 14, 2026
  • Straight line passing through the origin and the first and third quadrant.
  • Straight line passing through the origin and the second and fourth quadrant.
  • Straight line passing through the point $(1, -1)$ and having slope $-1$ .
  • Straight line passing through the point $(2, 1)$ and having slope $\frac{1}{2}$.
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The Correct Option is A

Solution and Explanation

Let's solve the equation \(|z + 1 - i| = |z - 1 + i|\) to understand what geometric shape it represents. Here, \(z\) is a complex number expressed as \(z = x + yi\), where \(x\) and \(y\) are real numbers, and \(i\) is the imaginary unit.

The expression \( |z + 1 - i| \) is the distance from the point \(z\) to the point \((-1, 1)\) on the complex plane. Similarly, \( |z - 1 + i| \) is the distance from \(z\) to the point \( (1, -1) \).

The given equation states that the distance from \(z\) to \((-1, 1)\) is equal to the distance from \(z\) to \( (1, -1) \). Geometrically, this is the definition of the perpendicular bisector of the line segment joining the points \((-1, 1)\) and \( (1, -1) \).

The midpoint of these points is:

\(\left( \frac{-1 + 1}{2}, \frac{1 - 1}{2} \right) = (0, 0)\)

The slope of the line segment joining \((-1, 1)\) and \( (1, -1) \) is:

\(\frac{-1 - 1}{1 + 1} = -1\)

The perpendicular bisector of a line segment will have a slope that is the negative reciprocal of \(-1\), which is \(1\). Hence, the perpendicular bisector is a line passing through the origin \((0, 0)\) with a slope of \(1\), represented by the equation:

\(y = x\)

This line passes through the origin and lies in the first and third quadrants. Therefore, the correct answer is:

Straight line passing through the origin and the first and third quadrant. 
 

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